Chemistry - Mole Concept Question with Solution | TestHub
ChemistryMole ConceptCalculation of moleMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
A 4.47 g sample of a mixture of and was dissolved in water and mixed thoroughly with a 5.74 g portion of AgCl. After the reaction the solid, a mixture of AgCl and AgBr, was filtered, washed, and dried. Its mass was found to be
No. of moles of ion present in the solution after precipitation are :
Options:
Answer:
D
Solution:
Initial AgCl moles = .
From previous calculation, AgBr formed = , so AgCl consumed = .
Remaining AgCl = (in precipitate).
CuCl₂ formed from reaction contains Cl⁻ ions = .
CuBr₂ = , so CuCl₂ = .
Total Cl⁻ in solution = remaining chloride ions + CuCl₂ chloride = .
Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole
⏱ 2mℹ️ Source: QB
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