Chemistry - Mole Concept Question with Solution | TestHub

Question Explanation: Determine the remaining volume of water after removing a specific number of moles from an initial quantity of water molecules.

Given Data:

Initial number of water molecules: $3.01\times 10^{24}$ molecules

Number of moles of water removed: $0.5$ moles

Concept:

$$MOL=\frac{noofmolecules}{6.02\times 10^{23}}$$

Mathematical Calculation:

Calculate initial moles of water:

Initial moles of water = (Number of water molecules) / (Avogadro's number)

Initial moles of water = $(3.01\times 10^{24}molecules)/(6.022\times 10^{23}molecules/mol)$

Initial moles of water = $5$ moles

Calculate remaining moles of water:

Remaining moles of water = Initial moles of water - Moles of water removed

Remaining moles of water = $5moles-0.5moles=4.5moles$

Calculate remaining volume of water:

Remaining Mass = Remaining moles of water $\times$ Molar Mass

Remaining Mass = $18g/mol\times 4.5mol=81g$

Remaining Volume = Mass / Density of water ($1g/mL$)

Remaining Volume = $81g/1g/mL=81mL$

Final Answer: The remaining volume of water is $81mL$.