Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediuminteger

$12 g K_{2} CO_{3}$ was treated by a series of reagents so as to convert all of its carbon to $K_{2} Zn_{3} [Fe (CN)_{6}]_{2}$ . Calculate the weight of the product.

[mol. wt. of K₂CO₃ = 138 and mol. wt. of K₂Zn₃ [Fe(CN)₆]₂ = 698]

Answer:

Solution:

wt. of $K_{2} Zn_{3} [Fe (CN)_{6}] = \frac{12}{138} \times \frac{698}{12} = 5$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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