Chemistry - Mole Concept Question with Solution | TestHub

Assume $100g$ of compound:

S = 16 g, C = 4 g, O = 4 g

Moles:

S: $\frac{16}{32}=0.5$

C: $\frac{4}{12}=\frac{1}{3}$

O: $\frac{4}{16}=0.25$

Divide by the smallest value (0.25):

S: $\frac{0.5}{0.25}=2$

C: $\frac{1/3}{0.25}=\frac{1}{3}\times 4=\frac{4}{3}$

O: $\frac{0.25}{0.25}=1$

So, S:C:O = $2:\frac{4}{3}:1$

Multiply by 3 to get whole numbers:

S:C:O = $6:4:3$

Empirical formula = C₄O₃S₆

Number of C, O, and S atoms = $4+3+6=\boxed{13}$