Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleEasy2 minQB

ChemistryEasysingle choice

In alkaline conditions, KMnO₄ reacts as $2 K M n O_{4} + 2 K O H ⟶ 2 K_{2} M n O_{4} + H_{2} O + [O]$ .

Therefore, its equivalent weight is

Answer:

Solution:

Oxidation state of Mn changes by 1 shows that the equivalent weight

$Eq u i v a l e n tw e i g h t = \frac{M o l ec u l a r w e i g h t}{n f a c t or} = \frac{M o l ec u l a r w e i g h t}{1}$

∴ $Eq u i v a l e n tw e i g h t = M o l ec u l a r w e i g h t$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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