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ChemistryMole ConceptMiscellaneous/MixedMedium2 minQB
ChemistryMediuminteger

A metallic chloride, denoted as (A) reacts with NaOH in the presence of to yield a yellow - colored solution containing salt (B) On adding dilute , the solution turns orange due to the formation of compound (C).

When compound (D) is heated with (C) in the presence of concentrated H₂SO₄, a red, volatile compound (E) is generated. Compound (E), upon absorption in NaOH, regenerates a yellow solution of salt (B), which produces a yellow precipitate on treatment with acidified lead acetate solution.

Compound (C), when reacted with NH₄Cl, gives compound (F), which on heating decomposes into a green solid (G), water, and a colorless gas. Moreover, compound (D) imparts a golden-yellow flame color.

Identify the compounds (A) through (G) and calculate the total number of atoms per formula unit of A, B, C, D, E, F, G.

Answer:
53
Solution:

Identifications (A → G)

A = CrCl₃ (chromium (III) chloride)

4

B = Na₂CrO₄ (chromate ion; yellow in basic medium)

7

C = Na₂Cr₂O₇ (dichromate ion; orange in acidic medium)

11

D = NaCl (sodium chloride - gives golden-yellow flame)

2

E = CrO₂Cl₂ (chromyl chloride, red, volatile liquid)

5

F = (NH₄)₂Cr₂O₇ (ammonium dichromate)

19

G = Cr₂O₃ (chromium (III) oxide; green residue)

5

 

53

 

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed
2mℹ️ Source: QB

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