Chemistry - Mole Concept Question with Solution | TestHub

$\underset{1\text{mol}}{{\mathrm{H}}_2{\mathrm{O}}_2}+\underset{1\text{mol}}{{\mathrm{H}}_2\mathrm{S}}\to 2{\mathrm{H}}_2\mathrm{O}+\mathrm{S}$
0.1 mol${\mathrm{H}}_2\mathrm{S}$require${\mathrm{H}}_2{\mathrm{O}}_2=0.1$mol
Molarity of 22.4 volume${\mathrm{H}}_2{\mathrm{O}}_2=\frac{22.4}{11.2}=2\text{M}$
Now volume of${\mathrm{H}}_2{\mathrm{O}}_2$required
$=\frac{\mathrm{m}\mathrm{o}\mathrm{l}}{\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{a}\mathrm{r}\mathrm{i}\mathrm{t}\mathrm{y}}=\frac{0.1}{2}\mathrm{L}$
$=\frac{0.1\times 1000}{2}=50\text{mL}$