1.44 g of Titanium (Ti) reacted with an excess of O 2 and produced x g of a non-stoichiometric compound Ti 1.44 O 1 . The value of x in g is :

Ti + O 2 ⟶ Ti 1.44 O (1.44 g) (x) g Apply POAC to Ti ( 1.44 g 48 ) × 1 = { x g ( 1.44 × 48 ) + 16 } 1.44 x = 4 8 × 1 . 4 4 + 1 6 4 8 = 1 . 4 4 + 1 6 4 8 = 1.44 + 0.33 = 1.77 g.

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

1.44 g of Titanium (Ti) reacted with an excess of O₂and produced x g of a non-stoichiometric compound Ti_1.44O₁. The value of x in g is :

Options:

Answer:

Solution:

Ti + O₂ $⟶$ Ti_1.44O

(1.44 g) (x) g

Apply POAC to Ti

$(\frac{1.44 g}{48}) \times 1 = {\frac{x g}{(1.44 \times 48) + 16}} 1.44$

x = $\frac{48 \times 1.44 + 16}{48}$

= $1.44 + \frac{16}{48}$

= 1.44 + 0.33

= 1.77 g.

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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