Chemistry - Mole Concept Question with Solution | TestHub

To find the grams of SO₃ produced from 1 mol of S₈, we use stoichiometry.

From the first reaction:

S₈ + 8O₂(g) → 8SO₂(g)

1 mol S₈ produces 8 mol SO₂.

From the second reaction:

2SO₂(g) + O₂(g) → 2SO₃(g)

8 mol SO₂ will produce 8 mol SO₃ (since the ratio is 2:2 or 1:1).

Molar mass of SO₃ = $32.07+3\times 16.00=80.07$ g/mol.

Mass of SO₃ = $8mol\times 80.07g/mol=640.56g$.

Rounding to appropriate significant figures, we get 640 g.