Chemistry - Mole Concept Question with Solution | TestHub

Balanced reaction can be given as
$\underset{24\times 2=48}{2\mathrm{M}\mathrm{g}}+\underset{32}{{\mathrm{O}}_2}\to 2\mathrm{M}\mathrm{g}\mathrm{O}$
32 g of${\mathrm{O}}_2$is required to burn 48 g Mg
So, 0.28 g${\mathrm{O}}_2$will be required for$\frac{48}{32}\times 0.28$g Mg
$=0.42$g of Mg
Thus, Mg will remain in excess$=1-0.42=0.58$g