Chemistry - Mole Concept Question with Solution | TestHub
ChemistryMole ConceptCalculation of moleMedium2 minQB
ChemistryMediummatching list
Match the following:
Column I | Column II |
|---|---|
(A) 100 ml of solution +400 ml of 0.1 M HCl solution | (P) Total concentration of cation(s) = 0.12 M |
(B) 50 ml of | (Q) |
(C) 30 ml of | (R) |
(D) | (S) |
Options:
Answer:
C
Solution:
(A) Concentration of
Concentration of
Total cationic concentration
Concentration of in
Concentration of in
Total concentration
(B)
(C)
(D) Weight of
Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole
⏱ 2mℹ️ Source: QB
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