Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptDetection and Estimation of ElementsMedium2 minQB

ChemistryMediuminteger

All carbon atom present in $KH_{3} (C_{2} O_{4})_{2} \cdot 2 H_{2} O$ weighing 7.62 gm is converted to $CO_{2}$ . How many gm of $CO_{2}$ were obtained. ( $K = 39$ ) (Nearest Integer)

Answer:

Solution:

0.03 moles

Apply POAC for C.

$4 \times$ moles of $KH_{3} (C_{2} O_{4})_{2} \cdot 2 H_{2} O = 1 \times$ moles of $CO_{2}$

$4 \times 0.03 = 1 \times \frac{W}{44} \Rightarrow W = 5.28 gm$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Detection and Estimation of Elements

⏱ 2mℹ️ Source: QB

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Chemistry - Mole Concept Question with Solution | TestHub

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