Chemistry - Mole Concept Question with Solution | TestHub

$1\text{mol}=6.023\times {10}^{23}\text{molecules}$

$4.4\text{g}\text{C}{\text{O}}_2=\frac{4.4}{44}=0.1\text{mol}\text{C}{\text{O}}_2$

$\text{(Mol. wt. of}$$\text{C}{\text{O}}_2=44)$

$0.1\text{mol}=6.023\times {10}^{23}\times 0.1\text{molecules}$

$=6\times {10}^{22}\text{molecules}$

$=2\times 6\times {10}^{22}\text{atoms}\text{of}\text{O}$
=$1.2\times {10}^{23}$