Chemistry - Mole Concept Question with Solution | TestHub

Moles of ${\mathrm{CO}}_2=\frac{0.22}{44}=\frac{1}{200}$

Then,

Mass of $\mathrm{C}=\frac{0.220}{44}\times 12=0.06 \mathrm{g}$

$\%\mathrm{of} \mathrm{C}=\frac{0.06}{\mathrm{W}}\times 100=24$

(W= Wt.of organic compound)

$\mathrm{W}=0.25$

Moles of ${\mathrm{H}}_2\mathrm{O}=\frac{0.126}{18}=0.007$

Moles of $\mathrm{H}=0.007\times 2=0.014 \mathrm{g}$

$$\begin{gathered} \%\mathrm{of} \mathrm{Hydrogen}=\frac{0.014\times 1}{\mathrm{W}}\times 100 \\ =\frac{0.014\times 1}{0.25}\times 100 \\ =5.6 \end{gathered}$$

$=56\times {10}^{-1}$