An organic compound weighing 500 mg , produced 220 mg of $CO_{2}$ . on complete combustion. The percentage composition of carbon in the compound is _____ \%. (nearest integer)
(Given molar mass in $g mol^{- 1}$ of $C : 12, O : 16$ )

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TestHub · Accepted Answer

Organic compound CuO Δ ​ CO 2 ​ + H 2 ​ O ​ n CO 2 ​ ​ = 44 220 × 1 0 − 3 ​ = 5 × 1 0 − 3 moles m C ​ = 5 × 1 0 − 3 × 12 ​ % m carbon = 500 × 1 0 − 3 5 × 1 0 − 3 × 12 ​ × 100 = 12% Correct answer is 12

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