Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedMedium2 minPYQ_2010

ChemistryMediumnumerical

A student performs a titration with different burettes and finds titre values of $25.2 mL, 25.25 mL$ , and $25.0 mL$ . The number of significant figures in the average titre value is

Answer:

3.00

Solution:

Average $= \frac{25.2 + 25.25 + 25.0}{3} = \frac{75.45}{3} = 25.15 = 25.2 mL$ Number of significant figure is 3 . Basics in chemistry Rule application III (Difficulty level is high because of shear ignorance of such topics)

Stream:JEE_ADVSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2010

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