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ChemistryMole ConceptLaws of Chemical CalculationsMedium2 minQB

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Volume of $0.1 M K_{2} Cr_{2} O_{7}$ required to oxidize 35 mL of $0.5 M FeSO_{4}$ solution is

Answer:

Solution:

meq of K₂Cr₂O₇ = meq of FeSO₄

$0.1 \times 6 \times V = 35 \times 0.5 \times 1$

So, $V = 29.2 m L$ .

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Laws of Chemical Calculations

⏱ 2mℹ️ Source: QB

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