Zinc and hydrochloric acid react according to the following reaction : Z n s + 2 H C l a q . → Z n C l 2 ( a q . ) + H 2 ( g ) If 0.30 m o l e o f Zn is added to 0.52 m o l e HCl, how many moles of H 2 is produced?

∵ M o l e r a t i o o f Z n : H C l : H 2 i s 1 : 2 : 1 2 mole HCl gives = 1 mole H 2 0.52 mole HCl gives = 1 × 0.52 2 = 0.26 mole Note that H C l is used completely and thus it is limiting reagent.

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Zinc and hydrochloric acid react according to the following reaction :
$Z n (s) + 2 H C l (a q .) \to Z n C l_{2} (a q .) + H_{2} (g)$
If $0.30 m o l e o f Zn is$ added to $0.52 m o l e HCl,$ how many moles of $H_{2}$ is produced?

Options:

Answer:

Solution:

$∵ M o l e r a t i o o f Z n : H C l : H_{2} i s 1 : 2 : 1$
$2 mole HCl gives = 1 mole H_{2}$
$0.52 mole HCl gives = \frac{1 \times 0.52}{2} = 0.26 mole$
Note that $H C l$ is used completely and thus it is limiting reagent.

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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