Chemistry - Mole Concept Question with Solution | TestHub

Number of moleules$\propto$Number of moles
(A) Moles of water$=\frac{0.00224}{22.4}=10^{-4}$
Molecules of water$=\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\times {\mathrm{N}}_{\mathrm{A}}=10^{-4}{\mathrm{N}}_{\mathrm{A}}$
(B) Molecules of water$=\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\times {\mathrm{N}}_{\mathrm{A}}=\frac{0.18}{18}{\mathrm{N}}_{\mathrm{A}}=10^{-2}{\mathrm{N}}_{\mathrm{A}}$
(C) Mass of water$=18\times 1=18\mathrm{g}$
Molecules of water$=\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\times {\mathrm{N}}_{\mathrm{A}}=\frac{18}{18}{\mathrm{N}}_{\mathrm{A}}={\mathrm{N}}_{\mathrm{A}}$
(D) Molecules of water$={10}^{-2}\text{mole}={10}^{-2}{\text{N}}_{\text{A}}$
Hence 18 ml${\mathrm{H}}_2\mathrm{O}$has maximum molecules.