Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

How many carbon atoms are present in $0.35 m o l e$ of $C_{6} H_{12} O_{6} ?$
(Given: $N_{A} = 6.023 \times 10^{23}$ )

Options:

Answer:

Solution:

$∵ 1 m o l e o f C_{6} H_{12} O_{6} h a s = 6 N_{A}atomsofC$

$0.35 m o l e o f C_{6} H_{12} O_{6} h a s = 6 \times 0.35 N_{A}atomsofC=2.1N_{A}atoms$

$= 2.1 \times 6.023 \times 10^{23} = 1.26 \times 1 0^{24} c a r b o n a t o m s$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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