Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedMedium2 minPYQ_2020
ChemistryMediumnumerical

0.7grams ofNa2CO3.xH2Owere dissolved in water and the volume was made to 100 mL, 20 mL of this solution required 19.8 mL of N/10 HCl for complete neutralization. The value ofxis
Report your answer by rounding it upto nearest whole number.

Answer:
2.00
Solution:

Meq. of Na 2 CO 3 ⋅ xH 2 O in 20 mL=19.8× 1 10

∴Meq. of Na 2 CO 3 ⋅ xH 2 O  Na 2 CO 3 ⋅ xH 2 O in 100 mL=19.8× 1 10 ×5

∴wE×1000=19.8×110×5

or0.7M2×1000=19.82

∴  M=141.41

23×2+12+3×16+18x=141.41

∴  x≅2

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2020

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