N 2 ( g ) reacts with H 2 ( g ) in either of the following ways depending upon the supply of H 2 ( g ) . N₂(g) + H₂(g) → N₂H₂(g) N₂(g) + 2H₂(g) → N₂H₄(g) If 3 L of N₂(g) and 5 L of H₂(g) are tak

Question

N 2 ​ ( g ) reacts with H 2 ​ ( g ) in either of the following ways depending upon the supply of H 2 ​ ( g ) . N₂(g) + H₂(g) → N₂H₂(g) N₂(g) + 2H₂(g) → N₂H₄(g) If 3 L of N₂(g) and 5 L of H₂(g) are taken initially (at the same temperature and pressure), then the contraction in volume after the reaction (in L) is x . If 4 L of N₂(g) and 9 L of H₂(g) are taken initially, then the contraction in volume after the reaction (in L) is y . Calculate x y ​ .

TestHub · Accepted Answer

N 2 ​ + H 2 ​ → N 2 ​ H 2 ​ N 2 ​ + 2 H 2 ​ → N 2 ​ H 4 ​ For 3 L N₂ and 5 L H₂: Let N 2 ​ H 2 ​ = a and N 2 ​ H 4 ​ = b . a + b = 3 a + 2 b = 5 Solving these equations gives a = 1 and b = 2 . The final volume is 3 L, so: x = ( 3 + 5 ) − 3 = 5 L For 4 L N₂ and 9 L H₂: 4 L N₂ consumes 8 L H₂ to form 4 L N₂H₄. Remaining H₂ = 1 L, final volume = 5 L. y = ( 4 + 9 ) − 5 = 8 L x y ​ = 5 8 ​ = 1.60

Chemistry - Mole Concept Question with Solution | TestHub

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