Chemistry - Mole Concept Question with Solution | TestHub

Let the number of moles of${\text{NaHCO}}_{\text{3}}$is$\text{x}\text{.}$
$\text{Wt}\text{.}\text{loss}\text{=}\frac{\text{x}}{\text{2}}\text{×}\text{44}\text{+}\frac{\text{x}}{\text{2}}\text{×}\text{18}$
$\text{\%}\text{Weight}\text{loss}=\frac{\frac{\cancel{\text{x}}}{2}\times 62}{\cancel{\text{x}}\times 84}\times 100$
$=36.9\%$