Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

Calculate milli equivalent of washing soda required to remove its hardness from one litre hard water contains 18.00 mg $M g^{2 +}$

Answer:

1.50

Solution:

Meq of $M g^{+ 2} \equiv$ Meq of washing soda

$\frac{W}{E} \times 1000 = M g^{+ 2}$ ; $E W = \frac{24}{2} = 12$

$\frac{18 \times 1 0^{- 3}}{12} \times 1000 = 1.5$

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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