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ChemistryMole ConceptExpetimental Determination of Atomic Mass/Molecuair massMedium2 minQB

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The degree of dissociation of A is $10%$ then find molecular weight of A for given reaction when vapour density of mixture is 60

A(g) → B(g) + C(g)

Answer:

Solution:

$α = \frac{M _{T} - M _{0}}{M _{0} ( n - 1 )} \Rightarrow 0.1 = \frac{M _{A} - 120}{120 \times 1}$

$\Rightarrow 12 = M_{A} - 120 \Rightarrow M_{A} = 132$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Expetimental Determination of Atomic Mass/Molecuair mass

⏱ 2mℹ️ Source: QB

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