Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Chlorine gas is prepared by reaction of $H_{2} S O_{4}$ with $M n O_{2}$ and NaCl. What volume of $C l_{2}$ will be produced at STP if 50 g of NaCl is taken in the reaction?

Options:

Answer:

Solution:

$\underset{\underset{(2 \times 58.5 = 117 g)}{2 moles}}{2 N a C l} + M n O_{2} + 3 H_{2} S O_{4} \to 2 N a H S O_{4} + M n S O_{4} + \underset{\underset{22.4 L (STP)}{1 mole}}{C l_{2}} + 2 H_{2} O$

117 g of NaCl $\equiv 22.4$ L of $C l_{2}$

50 g of $N a C l \equiv \frac{22.4}{117} \times 50 = 9.57$ L of $C l_{2}$ at STP.

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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