Suppose the elements P and Q combine to form two compounds P Q 2 and P 3 Q 2 . When 0.1 mole of P Q 2 weight 10 g and 0.05 mole of P 3 Q 2 weight 9 g, the atomic weights of P and Q are

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Let atomic weight of element P is p and that of element Q is q.

For $P Q_{2}, n = \frac{w}{M o l . w t .}$

$0.1 = \frac{10}{p + 2 q}$

$p + 2 q = \frac{10}{0.1} = 100$ ...(i)

For $P_{3} Q_{2}, n = \frac{w}{M o l . w t .}$

$0.05 = \frac{9}{3 p + 2 q}$

$3 p + 2 q = \frac{9}{0.05} = 180$ ...(ii)

On solving equation (i) and (ii) we get q = 30

$p + 2 (30) = 100$

$p = 100 - 60 = 40$

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