Chemistry - Mole Concept Question with Solution | TestHub

The reaction of ethylamine (CH₃CH₂NH₂) with NaNO₂/HCl produces dinitrogen gas (N₂).

CH₃CH₂NH₂ + NaNO₂ + HCl $\to$ CH₃CH₂OH + N₂ + NaCl + H₂O

At STP, 1 mole of any gas occupies 22.4 L.

Given volume of N₂ = 2.24 L.

Moles of N₂ = $\frac{2.24L}{22.4L/mol}=0.1mol$

From the stoichiometry, 1 mole of ethylamine produces 1 mole of N₂.

So, moles of ethylamine = 0.1 mol.

Molar mass of ethylamine (CH₃CH₂NH₂) = 2(12) + 7(1) + 14 = 24 + 7 + 14 = 45 g/mol.

Mass of ethylamine (X) = moles $\times$ molar mass = $0.1mol\times 45g/mol=4.5g$.

The question asks for X in the format $\_\_\_\_\times 10^{-1}g$.

$4.5g=45\times 10^{-1}g$.

So, X = 45.

The final answer is $\boxed{45}$.