3.92 g of ferrous ammonium sulphate react completely with 50 ml 10 N KMnO 4 solution. The percentage purity of the sample is

Eq of KMnO 4 used = 1000 × 10 50 × 1 = 0.005 ∴ Eq of FAS reacted = 0.005 ∴ weight of FAS needed = 0.005 × 392 = 1.96 g Thus percentage purity of FAS is 50%

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ChemistryMole ConceptMiscellaneous/MixedMedium2 minPYQ_2014

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$3.92 g$ of ferrous ammonium sulphate react completely with $50 ml \frac{N}{10} KMnO_{4}$ solution. The percentage purity of the sample is

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Solution:

Eq of $KMnO_{4}$ used $= \frac{50 \times 1}{1000 \times 10} = 0.005$ $∴$ Eq of FAS reacted $= 0.005$ $∴$ weight of FAS needed $= 0.005 \times 392 = 1.96 g$ Thus percentage purity of FAS is $50%$

Stream:BITSATSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2014

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