In Haber process 3 litres of dihydrgen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the abo

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In Haber process 3 litres of dihydrgen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the above said condition in the end?NEET 2003

TestHub · Accepted Answer

N 2 ​ + 3 H 2 ​ → 2 NH 3 ​ 1 mol 3 mol 2 mol 2 vol 3 mol 2 vol ( mol % = vol % ) ​ 10 vol 30 vol 20 vol (expected = product) ​ ( 30 − x ) ( 30 − x ) 2 x Given that 2 x = 20 × 100 50 ​ = 10 ∴ x = 5 ​ Composition of gaseous mixture N 2 ​ H 2 ​ NH 3 ​ ​ = ( 30 − x ) = 25 litre = ( 30 − 3 x ) = 15 litre = 2 x = 10 litre ​

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