Chemistry - Liquid Solution Question with Solution | TestHub

The vapour pressure of a dilute aqueous solution of glucose is 750 mm of Hg at 373 K. The mole fraction of solute is-

Given:

Vapour pressure of solution ($P_s$) = 750 mm Hg

Temperature = 373 K

At 373 K (100 °C), the vapour pressure of pure water ($P^0$) is 760 mm Hg.

According to Raoult's Law for dilute solutions:

$$\frac{P^0-P_s}{P^0}=X_{solute}$$

Where $X_{solute}$ is the mole fraction of the solute. \

Substitute the given values:

$$X_{solute}=\frac{760-750}{760}=\frac{10}{760}=\frac{1}{76}$$

Thus, the mole fraction of the solute is $\frac{1}{76}$.

The final answer is $\frac{1}{76}$.