Chemistry - Liquid Solution Question with Solution | TestHub

$\mathrm{KI}(\mathrm{aq})+{\mathrm{AgNO}}_3(\mathrm{aq})⟶\mathrm{AgI}(\mathrm{s})\downarrow +{\mathrm{KNO}}_3(\mathrm{aq})$

$\mathrm{KI}+{\mathrm{AgNO}}_3⟶{\mathrm{KNO}}_3+\mathrm{AgI}\downarrow$

Initial : 0.3 mole 0.2 mole - -

Final: 0.1 mole - $0.20.2$

Total moles of solute ions $=(0.1+0.2)\times 2(\therefore \mathrm{i}=2)$

$$\begin{gathered} \text{displaylines}\begin{array}{rlr}& [\text{ Solute }]=\frac{0.6}{4}\mathrm{M}& \end{array} \\ \Delta {\mathrm{T}}_{\mathrm{f}}={\mathrm{K}}_{\mathrm{f}}\cdot \frac{0.6}{4}=1.86\times \frac{0.6}{4}=0.279\mathrm{K} \end{gathered}$$