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ChemistryLiquid SolutionMiscellaneous/MixedMedium2 minQB

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$200 ml, 2 M Li_{3} PO_{4}$ solution is $80%$ ionised then find sum of mol of all ions in solution :-

Answer:

Solution:

$Li_{3} PO_{4} \to 3 Li^{+} + PO_{4}^{3 -}$

(0.4 mol)

0.4–0.4×0.8 3×0.4×0.8 0.4×0.8

0.96 + 0.32 = 1.28

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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