Chemistry - Liquid Solution Question with Solution | TestHub

$${\left(\Delta T_B\right)}_{K_4\left[Fe{\left(C{N}_{}\right)}_6\right]}={\left(\Delta T_B\right)}_A$$

$${\left(i{K}_{b}m\right)}_{K_4\left[Fe{\left(C{N}_{}\right)}_6\right]}={\left(i{K}_{b}m\right)}_A$$

For the same boiling point, the molality of another solution should be $2.2m$.

Now, an $18.1$ weight percent solution means $18.1gm$ of solute is present in $100gm$ of solution. Hence, $(100-18.1)=81.9gm$ of water.

Now, $2.2=\frac{\frac{18.1}{M}}{\frac{81.9}{1000}}$

$$Molarmassofsolute,M=100$$