Chemistry - Liquid Solution Question with Solution | TestHub

Moles of HCl in 100 ml solution $(\mathrm{I})=\frac{0.0365}{36.5}=10^{-3}$ moles

= moles of Cl⁻ ions.

The number of moles of Cl⁻ ions in solution (II) = $400\times 10^{-2}\times 10^{-3}=4\times 10^{-3}$ moles.

Moles of Cl⁻ ions in the resulting solution =$4\times 10^{-3}+10^{-3}=5\times 10^{-3}$ moles.

Molarity of Cl⁻ ions in the resulting solution =$\frac{5.0\times 10^{-3}}{0.5}=10^{-2}$ M.