Chemistry - Liquid Solution Question with Solution | TestHub

According to Henry's law, the solubility of a gas in a liquid is directly proportional to its partial pressure at a constant temperature.

$S\propto P$

$\frac{S_1}{P_1}=\frac{S_2}{P_2}$

Given $S_1=6.85\times 10^{-4}{\text{ mol L}}^{-1}$, $P_1=1\text{ bar}$, and $P_2=0.70\text{ bar}$.

$S_2=S_1\times \frac{P_2}{P_1}$

$S_2=6.85\times 10^{-4}\times \frac{0.70}{1}$

$S_2=4.795\times 10^{-4}{\text{ mol L}}^{-1}$

Answer: $4.795\times 10^{-4}{\text{ mol L}}^{-1}$