Chemistry - Liquid Solution Question with Solution | TestHub

Number of moles of solute, $n_2=\frac{W_2}{M_2}=\frac{394}{342}=1.152\text{ mol}$

Number of moles of solvent (water), $n_1=\frac{W_1}{M_1}=\frac{622}{18}=34.555\text{ mol}$

Total number of moles, $n=n_1+n_2=34.555+1.152=35.707\text{ mol}$

Mole fraction of solute, $x_2=\frac{n_2}{n_1+n_2}=\frac{1.152}{35.707}\approx 0.032$

Answer: 0.032