2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is :
(Given : Ebullioscopic constant of water $= 0.52 K kg mol^{- 1})$

Question

2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is : (Given : Ebullioscopic constant of water = 0.52 K kg mol − 1 )

TestHub · Accepted Answer

​ Δ T b ​ = i 1 ​ m 1 ​ k b ​ + i 2 ​ m 2 ​ k b ​ = 1 × 0.5 2 ​ × 0.52 + 0.5 1 × 2 ​ × 0.52 = 4.16 ( T b ​ ) solution ​ = 373.16 + 4.16 = 377.3 K . ​

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