Chemistry - Liquid Solution Question with Solution | TestHub

Sucrose $⟶$ No dissociation $\begin{array}{rl}& \mathrm{NaCl}⟶{\mathrm{Na}}^{+}+{\mathrm{Cl}}^{-}\\ & {\mathrm{CaCl}}_2⟶{\mathrm{Ca}}^{2+}+2{\mathrm{Cl}}^{-}\end{array}$ Elevation in boiling point is directly proportional to the number of particles and ${\mathrm{CaCl}}_2$ solution contains more number of particles. Hence, $\Delta T_b$ will be maximum for ${\mathrm{CaCl}}_2$ and so will be the boiling point.