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ChemistryLiquid SolutionMiscellaneous/MixedMedium2 minQB

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A 6.90 M solution of KOH in water has $30%$ of KOH by weight. The density of solution is [Atomic mass : $K = 39$ ]

Answer:

Solution:

Weight of KOH in 1 liter solution $= 6.9 \times 56 = \frac{30}{100} \times$ weight of solution.

Therefore, the weight of the solution is:

$w e i g h t o f so l u t i o n = \frac{6.9 \times 56}{0.3} = 1288 g$

The density of the solution is:

$d e n s i t yo f so l u t i o n = \frac{1288}{1000} g / m L = 1.288 g / m L$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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