Chemistry - Liquid Solution Question with Solution | TestHub

Molality of the solution is given by $m=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}$

$m=\frac{0.1}{0.2}=0.5{\text{ mol kg}}^{-1}$

Elevation in boiling point is $\Delta T_b=K_b\times m$

$\Delta T_b=0.513\times 0.5=0.2565^{\circ }\mathrm{C}$

Boiling point of the solution is $T_b=100^{\circ }\mathrm{C}+0.2565^{\circ }\mathrm{C}=100.2565^{\circ }\mathrm{C}\approx 100.256^{\circ }\mathrm{C}$

Answer: $100.256^{\circ }\mathrm{C}$