Chemistry - Liquid Solution Question with Solution | TestHub

$\text{Δ}{\text{T}}_{\text{b}}={\text{K}}_{\text{b}}\left(\frac{{\text{w}}_{\text{solute}}}{{\text{W}}_{\text{solvent}}}\times \frac{1}{{\text{M}}_{\text{solute}}}\right)\times 1000$

$1=\frac{1000\times 10}{100\times {\text{M}}_{{\text{AB}}_2}}\Rightarrow {\text{M}}_{{\text{AB}}_2}=100$

Similarly${\text{M}}_{{\text{A}}_2\text{B}}=140$

$100={\text{M}}_{\text{A}}+2·{\text{M}}_{\text{B}}$

and$140={2·\text{M}}_{\text{A}}+{\text{M}}_{\text{B}};$

${\text{M}}_{\text{A}}=60and{\text{M}}_{\text{B}}=20$

Alternative solution

$\frac{\Delta {\text{T}}_{\text{b}}}{{\text{K}}_{\text{b}}}=1=\frac{10}{\frac{{\text{M}}_{\text{A}}+2{\text{M}}_{\text{B}}}{\text{0.1}}}$

${\text{M}}_{\text{A}}+2{\text{M}}_{\text{B}}=100$........ (1)

$\frac{\Delta {\text{T}}_{\text{b}}}{{\text{K}}_{\text{b}}}=1=\frac{14}{\frac{{\text{2M}}_{\text{A}}+{\text{M}}_{\text{B}}}{\text{0.1}}}$

${2\text{M}}_{\text{A}}+{\text{M}}_{\text{B}}=140$........ (2)

${\text{M}}_{\text{A}}={\text{60, M}}_{\text{B}}=20$