200 ml of an aqueous solution of glucose ( C 6 H 12 O 6 ) has molarity of 0.01 M . Which of the following operations can be done to this solution so as to increase its molarity to 0.015 M ?

Question

200 ml of an aqueous solution of glucose ( C 6 ​ H 12 ​ O 6 ​ ) has molarity of 0.01 M . Which of the following operations can be done to this solution so as to increase its molarity to 0.015 M ?

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Question Explanation:

Question is asking about operations that can be done to given solution so as to increase its molarity to 0.015 M

Concept:

This question is based on concentration terms

Solution:

Moles of glucose

$\frac{200}{1000} \times 0.01 = 0.002$

on evoporating 50 ml water

solution becomes 150 ml

then its molarity

$\frac{0.002}{150 L} \times 1000$

$\frac{2}{150} = 0.013 M$

if 0.18 gram glucose added then moles of glucose added

$\frac{0.18 m o l \cdot}{0.180 L} = 0.001$

then moles of glucose

0.002+0.001

0.003

Then molarity

$M = \frac{0.003 m o l}{200 L} = 0.015 M$

on adding 50 ml water total volume = 250 ml

then molarity

$\frac{0.002 m o l \cdot}{0.250 L} = 0.008 M \cdot$

Final Answer: The correct option is (2).

Chemistry - Liquid Solution Question with Solution | TestHub

Options:

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