Calculate the pressure of gas if the solubility of gas in water at 2 5 ∘ C is 6.85 × 1 0 4 mol dm − 3 (Henry's law constant is 6.85 × 1 0 4 mol dm − 3 bar − 1 )

We know S = K H P In 1 dm 3 or 1 lit moles of gas dissolved is 6.85 × 1 0 4 ∴ p = 6.85 × 1 0 4 /6.85 × 1 0 4 = 1.0 bar.

Start Free Mock LoginAlready registered? Login here

Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionHenry's LawEasy2 minPYQ_2022

ChemistryEasysingle choice

Calculate the pressure of gas if the solubility of gas in water at $2 5^{\circ} C$ is $6.85 \times 1 0^{4} mol dm^{- 3}$ (Henry's law constant is $6.85 \times 1 0^{4} mol dm^{- 3} bar^{- 1}$ )

Options:

Answer:

Solution:

We know $S = K_{H} P$ In $1 dm^{3}$ or 1 lit moles of gas dissolved is $6.85 \times 1 0^{4}$ $∴ p = 6.85 \times 1 0^{4} /6.85 \times 1 0^{4} = 1.0$ bar.

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Henry's Law

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...