Chemistry - Liquid Solution Question with Solution | TestHub

Weight of Phenol$\left({\text{w}}_{\text{A}}\right)=\text{2}\text{.0}\times {10}^{-2}\text{ kg}=20\text{ g}$

Weight of Benzene$\left({\text{w}}_{\text{B}}\right)=\text{1}\text{.0 kg}$

$\text{Δ}{\text{T}}_{\text{i}}=\text{0}\text{.69 K}{\text{K}}_{\text{f}}=\text{5}{\text{.12 K kg mol}}^{-1}$

$\text{Δ}{\text{T}}_{\text{f}}={\text{i K}}_{\text{f}}\text{m}$

$\text{i}=\frac{\text{Δ}{\text{T}}_{\text{f}}}{{\text{K}}_{\text{f}}\text{m}}=\frac{\text{0}\text{.69}}{\text{5}\text{.12}\times \frac{20}{94}}=\frac{\text{0}\text{.69}\times 94}{\text{5}\text{.12}\times 20}\text{,}\text{i}=\text{0}\text{.63}$

$\begin{array}{ccc}2\text{A}& \rightleftharpoons & {\left(\text{A}\right)}_2\\ 1-\text{x}& & \text{x}/2\end{array}$

Particle after association   i$=1-\text{x}+\text{x}/2=1-\text{x}/2$

$\text{i}=1-\text{x}/2$

$\text{0.63}=1-\frac{\text{x}}{2}\text{x}\Rightarrow \text{0.734}$i.e.,$\text{73.4}\text{\%}$