Vapour pressure of solution and of pure solvent are P 1 and P 1 0 respectively. If P 1 0 P 1 is 0.15 , find the mole fraction of solute.

P 1 0 P 1 0 − P 1 = mole fraction of solute 1 − P 1 0 P 1 = x solute x solute = 1 − 0.15 = 0.85

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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2021

ChemistryEasysingle choice

Vapour pressure of solution and of pure solvent are $P_{1}$ and $P_{1}^{0}$ respectively. If $\frac{P _{1}}{P _{1}^{0}}$ is 0.15 , find the mole fraction of solute.

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Answer:

Solution:

$\frac{P _{1}^{0} - P _{1}}{P _{1}^{0}} = mole fraction of solute 1 - \frac{P _{1}}{P _{1}^{0}} = x_{solute} x_{solute} = 1 - 0.15 = 0.85$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2021

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