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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2020

ChemistryEasysingle choice

If 0.15 g of a solute, dissolved in 15 g of solvent, is boiled at a temperature higher by $0.216 ℃$ than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is $2.16 ℃)$ is

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Answer:

Solution:

weight of solute (w) =0.15 g, weight of solvent (W)=15 g,

$∆ T_{b}$ =0.216 $℃$

$k_{b}$ = 2.16 $℃$

$∴$ M= $\frac{k_{b} \times w \times 1000}{∆ T_{b} \times W}$

$= \frac{2.16 \times 0.15 \times 1000}{0.216 \times 15} = 100$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2020

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