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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

Depression in freezing point of 0.01 molal aqueous HCOOH solution is 0.02046°C. 1 molal aqueous urea solution freezes at –1.86°C. Assuming molality equal to molarity, calculate the pH of HCOOH solution.

Answer:

3.00

Solution:

1.86 = K_f(1)

0.02046 = (1 + $α$ ) × 1.86 × 0.01

$\Rightarrow 1 + α = \frac{0.02046}{0.0186} = 1.1$

$\Rightarrow α$ = 0.1

[H⁺] = C $α$ = 0.01 × 0.1 = 10^–3

so, pH = 3.

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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