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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

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Vapour pressure of a solution of $5 g$ of non- electrolyte in $100 g$ of water at a particular temperature is $2985 N / m^{2}$ . The vapour pressure of pure water is $3000 N / m^{2}$ . The molecular weight of the solute is

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Answer:

Solution:

$\frac{P^{o} - P_{s}}{P^{o}} = \frac{\frac{W_{2}}{M_{2}}}{\frac{W_{1}}{M_{1}}}$

$= \frac{3000 - 2985}{3000} = \frac{\frac{5}{M_{2}}}{\frac{100}{18}} or M_{2} = 180$

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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