Chemistry - Liquid Solution Question with Solution | TestHub

$\text{π}=\text{CRT}=\frac{{\text{W}}_{\text{B}}\times \text{R}\times \text{T}}{{\text{M}}_{\text{B}}\times \text{V}}$

For both solutions, R, T and V are constants.

For I solution

$\left(\text{4.98 bar}\right)=\frac{\left(\text{36g}\right)\times \text{R}\times \text{T}}{\left({\text{180 g mol}}^{-1}\right)\times \text{V}}\text{...(i)}$

For II solution

$\left(\text{1.52 bar}\right)=\frac{{\text{W}}_{\text{B}}\times \text{R}\times \text{T}}{{\text{M}}_{\text{B}}\times \text{V}}\text{...(ii)}$

On dividing Eq. (ii) by Eq. (i), we get

$\frac{\left(\text{1.52 bar}\right)}{\left(\text{4.98 bar}\right)}=\frac{{\text{W}}_{\text{B}}\times \text{R}\times \text{T}}{{\text{M}}_{\text{B}}\times \text{V}}\times \frac{\text{180}\times \text{V}}{\text{36}\times \text{R}\times \text{T}}$

$\frac{{\text{W}}_{\text{B}}}{{\text{M}}_{\text{B}}}=\frac{\text{1.52}}{\text{4.98}\times 5}={\text{0.0610 mol L}}^{-1}$